Subiectul al III-lea, 2. c)

Reguli generale:

2. c) ∫₀¹ x² f(x³ + 1) dx = (1/3)∫₁² f(t) dt = (1/3)(∫₁² (2t + 3) dt − 2∫₁² ln t dt) = - 3p = (1/3)[t² + 3t − 2t ln t + 2t]₁² = (1/3)(4 + 6 − 4 ln 2 + 4 − 1 − 3 − 2) = 4(2 − ln 2)/3 - 2p