Subiectul al III-lea, 2. b)

∫₁² (f(x) + 1/x) ln x dx = ∫₁² x ln x dx = ∫₁² (x²/2)′ ln x dx = [(x²/2) ln x]₁² − ∫₁² (x²/2) · (1/x) dx = - 3p = (4/2) ln 2 − (1/2) ln 1 − [x²/4]₁² = 2 ln 2 − 3/4 - 2p