Subiectul al II-lea, 1. b)

b)

A(−1) = ⎛ 0   1 ⎞,
        ⎝ 2  −1 ⎠
A(−1)·A(x) = ⎛  −2x      2x + 1 ⎞ =
             ⎝ 4x + 2   −4x − 1 ⎠

- 3p

= ⎛ (−2x − 1) + 1      −(−2x − 1)    ⎞ = A(−2x − 1), pentru orice număr real x
  ⎝ −2(−2x − 1)       2(−2x − 1) + 1 ⎠

- 2p